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# 3 HP motor power consumption per hour

3 mechanical horsepower equals 2.237 KW of power. In 1 hour this equates to 2.237 kWh of energy consumption. If your angle here is - how much energy/fuel will it take to run a 3HP motor for 1 hour? In which case you need to know two things: * ho.. The above calculations are suitable for DC motor, AC single phase motor and 3 phase motor. Example: Calculate the total power consumption of the 3 Phase 30HP motor is operating for 38 days at 70% of the full load and the motor is operated at 14 hours per day. Step1: First calculate the total number of hours. T (h) = 38 * 14 = 532 hours 1 Horsepower is equal to 745.7 watts of electrical power, so in theory a 5HP motor operating at 100% efficiency will consume about 3.728kW of power. In one hour, it will use 3728.5 kilowatt-hours. Of course, no motor is 100% efficiency, so the motor will actually consume somewhat more power than this

### What will be the power consumption for a 3 HP motor in one

1. 3 HP Treadmill Motor Power Consumption. 2 HP = 2237 Watts. So, a 3 HP treadmill will use 2237 Watts or 2.237 KiloWatts. So, it will consume 2.237 Units of electricity per hour. Please note that these are approximate values, and the real-world usage will be different depending on the other factors that we've discussed. Treadmill Power.
2. Calculate three-phase motor power consumption by multiplying amps by volts by the square root of three (W = AV(sqrt 3). For example, if the motor is drawing 30 amps at 250 volts, you have 30 x 250 x sqrt 3 (about 1.73) = 12,975 watts). Convert watts to kilowatts by dividing the number of watts by 1,000
3. With the motor load calculator you can quickly estimate annual energy use and cost for any electric motor. The calculator is a versatile energy management tool which accepts measured current, full load amps or rated horsepower inputs
4. Figure 3 Relationships Between Power, Current, Power Factor and Motor Load Example: Input Power Calculation An existing motor is identified as a 40-hp, 1800 rpm unit with an open drip-proof enclosure. The motor is 12-years old and has not been rewound. The electrician makes the following measurements: Measured Values: V ab = 467V I a = 36 amps.

* As you know for power consumption we are generally expressing in UNITS * 1 UNIT = 1kWh * 1 HP = 746 W = 0.746 kW * Therefore for 5 HP we get (5×0.746) = 3.73 kW * And by multiplying with hours we can get UNITS consumed by the 5 HP motor * And t.. Calculate the power the motor consumes while in operation. The equation is W = AV(sqrt 3) where A is amperes, V is volts, and sqrt 3 is the square root of 33 (about 1.73). W is the power consumption in watts. For example, if the electric motor uses 50 amps at 240 volts, the wattage is 50 x 240 x 1.73, or 20,760 watts

A 1 HP motor is supposed to deliver power equivalent to 746 Watts, or in other words, the rotational mechanical energy delivered by the shaft of the motor is rated to be equal to 746 Watts or .746 kW. This .746 kW is the net result delivered by th.. 1. Daily Power Consumption. Daily Power Consumption = Wattage rating x time in hours. 2000 Watts x 3 Hrs = 6000 Watts-Hour. Daily Power Consumption = 6 kWh. 2. Monthly Power Consumption. Monthly Power Consumption = Wattage rating x time in hours. 2000 Watts x 3 Hrs x 30 days = 180000 Watts-Hour. Monthly Power Consumption = 180 kWh. 3. Annual. Electrical Input Power = (Output Power/Efficiency). Assuming 90% efficiency, Input Power = 0.746/0.9 = 0.83kW. So, the consumed units of electricity = Power in kW X numbers of hours of operation = 0.83 units (assuming the motor is running for an hour). Now, I want to calculate the units of electricity consumption on the basis of load Horsepower (hp) is the name of several units of measurement of power, the rate at which work is done. This tool converts horsepower to btu per hour (hp to btu/h) and vice versa. 1 horsepower = 2544.4336113065 btu per hour

I'm here from the mechanical side. Need help on understanding power consumption on a 3 phase induction motor. I was trying to calculate electrical cost of operation on a 3 phase induction motor. I used the formula Kw=V*A*1.73*PF/1000 for my calculations out of a electrician's pocket reference book Cost per Day = 18 hr x \$.1971/KwHr = \$3.5478 or \$3.55 Cost per Week = 18 hr x 7 days x \$.1971/KwHr = \$24.8346 or \$24.83 Let's say the motor plate does not list the Kilowatt Rating nor is lit listed in literature or a web site and a representative is not available to help 3 HP = 3.17 kWh. The equation used above to determine kWh is Multiply the pool pumps volts x amps to get watts then divide by 1000. Step 2 - Daily Energy Consumption. Multiply your pumps kWh by the number of hours per day you run your pump. Here is an example using a 1-½ HP Pool Pump running 8 hrs. per day (Use kWh from step 1 HP is a unit of power, and as power is energy per time, power per hour is a meaningless concept. 1 HP is 746 watts, so 50 HP = 37300 watts or 37.3 kW If you want the energy used per hour, that is 37.3 kW-hour. The first step to convert HP to amps is convert HP to watts. Since 1 HP is equal to 746 W simply multiply the horsepower by 746 for this conversion. Watts = Horsepower × 746. Account for Efficiency. Since motors are not 100% efficient, the number of amps needed to achieve the power output is actually higher depending on the efficiency

Use water pump power consumption calculator to calculate power consumption of your 1/4 hp pump, 1/2 hp pump, 1 hp pump. Electricity consumption of any pump. For example a 50 watt TV consumes power at a rate of 50 watts per hour, it does not mean that the TV consumed 50 units of electricity, it means it will consume power at a rate of 50. Power Consumption in Metric Units. The power consumption for pumping water can be expressed in metric units as. P = q h ρ / (6116 10 3 μ) (3) where . P = power (kW) q = flow (liter/min) h = head (m) ρ = density (kg/m 3) (water 1000 kg/m 3) μ = pump efficiency (decimal value) Example - Power Required to Pump Wate Question: Estimate the monthly cost of 1 Ton AC that runs for 3 hours daily, If the bill is charged at \$0.05/kWh. Answer: 1 ton ac = 1200 watt = 1.2 kW. kWh For 3 hours daily = 3 * 1.2 kWh = 3.6 kWh. At rate of \$0.05/kWh bill becomes = 3.6 kW * \$0.05/kWh = \$0.18. Question: Estimate the running cost of 1.5 Ton AC for 5 hours daily @ rate \$0.1/kW Let's explore how to calculate the power consumption of a pump based on a (3 kilowatts) x (\$ 0.10 per kW hour) = \$1.80 per day To find the cost to operate per year, multiply by the number of days in a year: EXAMPLE: Let's use a single phase, ½ HP pump used in a STEP system. A time dosing panel i NOTES: To avoid damage to your motor or pump, it is recommended that the generator be started and permitted to come up to voltage before the pump or motor is turned on. A majority of industrial generators are externally regulated. Generators must be sized to deliver at least 65% of the rated voltage during motor starting to ensure adequate motor starting torque

### Electric Motor Power Consumption Calculator & 3 Phase

• Power Consumption = 2240 Watts Cost per hour (based on 13 cents per kWh) = \$0.29 Flow per hour = 4920 Gallons Cost per 24 hours = \$6.96 Flow per 24 hours = 118,080 Gallons 1730 RPM Flow Rate = 38 GPM Power Consumption = 360 Watts Cost per hour (based on 13 cents per kWh) = \$0.047 Flow per hour = 2280 gallons Cost per 24 hours = \$1.1
• i have a 5 hp motor in my factory . at load, it shows 3.5 ampere consumption ( when tested by a meter). is the consumption accurate? someone told me that 5 hp three phase motor will consume 7.5 ampere. what will be the unit consumption if it consumes 3.5 ampere. a detailed reply would be appreciated. thank
• Power consumed by Split AC 5 Star Split AC Electricity Consumption. 1.0 Ton Split AC - 0.98 kW per hour (Approx 1.0 unit per hour) 1.5 Ton Split AC - 1.49 kW per hour (Approx 1.5 unit per hour) 2.0 Ton Split AC - 1.73 kW per hour (Approx 1.7 unit per hour) 3 Star Split AC Electricity Consumption
• Select MerCruiser Test Model HP Fuel consumption WOT; MerCruiser 3.0 MPI/TKS - 181 cid. 135 hp: 10.5 GPH: MerCruiser 4.3 TKS - 262 ci
• RE: power consumption by 30 hp motor busbar (Electrical) 12 Apr 02 15:41 My point is that kVA-demand metering [common in Canada] by default takes care of both real and reactive components, and doesn't care about power factor or distortion components; provided the (analog-to-digital converter's) sampling rate is high enough
• The starting watts for a motor are obtained by multiplying the locked rotor current by the AC voltage. 3. Induction Motor running watts obtained from the National Electric Code Handbook. The above power ratings should only be used as a guide. 1/4 HP: 750 - 1500: 700: 1/2 HP: 1500 - 3000: 1175: 1 HP: 3000 - 6000: 1950: 2 HP: 4000 - 8000: 290

If you assume the motor is actually doing 20 HP worth of work, the resulting consumption will be 20 HP x 0.746 = 15 kW. Operating the motor for an hour will result in 15 kWh. In the real world I suspect the actual load will be closer to 10 to 12 kW on your 20 HP motor RLA - Running Load Amps - current drawn during normal operation of electric motor. FLA - Full Load Amps - amount of current drawn when full-load torque and horsepower is reached for the motor.FLA is usually determined in laboratory tests.Note! - in the calculator above FLA is RLA + 25%. 1 hp = 0.745 kW; Related Mobile Apps from The Engineering ToolBox.

### How much electricity does an electric motor use

1 hp(I) = 745.699872 W. So the power conversion of horsepower to watts is given by: P (W) = 745.699872 ⋅ P (hp) Example. Convert 10 hp to watts: P (W) = 745.699872 ⋅ 10hp = 7456.99872 W . Electrical horsepower to watts. One electrical horsepower is equal to 746 watts: 1 hp(E) = 746 W. So the power conversion of horsepower to watts is given. Power consumption (active) = (Supply voltage x sq root 3 (for 3 phase) x Amps drawn x cos phi at load point) / Efficiency e.g. (25hp) full load 400v 33Aflc 90%eff 0.82 cos phi (100% load) If you know the cos phi, you can calculate the VA (Watts) and VAr (apparent power) as needed, this is the part many people do not measure Typical Efficiencies 60.0 65.0 70.0 75.0 80.0 85.0 1970 1975 1980 1985 1990 1995 2000 2005 Year Average AFUE 6.00 7.00 8.00 9.00 10.00 11.00 12.00 1950 1960 1970 1980 1990 2000 201 The larger the rating, the more power the battery can hold, and the longer it will be able to power a motor at a given speed. For example, a 100 amperage hour battery is one that would be able to supply 25 amps of power for 4 hours (25 amps * 4 hours = 100 amp hours) before running out of energy Energy consumption calculator. kWh calculator. Energy consumption calculation. The energy E in kilowatt-hours (kWh) per day is equal to the power P in watts (W) times number of usage hours per day t divided by 1000 watts per kilowatt

Convert kWh to hp. Calculate horse power from kilowatt hour. Convert kWh to hp. Note: Kilowatt-hour (kWh) is a measure of energy and horsepower (hp) is a measure of power. Therefore you can only convert kilowatt-hour (kWh) directly to horsepower hour (hph) or kilowatts (kW) directly to horsepower (hp). 1 kW = 1.3404825737 hp Domestic fridge power consumption is typically between 100 and 250 watts. Over a full day, a fridge is likely to use between 1 to 2 kilowatt-hours (kWh). This translates into a running cost of about \$150 per year per fridge. Before you think okay great - now I know how much power my fridge uses - sorry to say, but i 3- During our Heating season, On Average- Our Blower motor on our Furnance runs only for 4 min every ave of 20 min. x3 per hour = 12 min an hour.. Ave out to @ x 24 hrs = 288 min per 24 hr day by 60 min = 4.8 hrs every 24 hrs . 3 of the 6 mos a heating season it only runs the ave of 2x per hour and during the coldest months or 3 mos a yr, it. The fuel consumption rate for many makes of Diesel Engines can be found in a range between 0.380 & 0.450 lbs/hp hour; 172 & 181 grams/hp hour; 231 & 243 grams/kW hour. This does not represent a big difference in fuel consumption per power unit between most normal naturally aspirated diesel engines, while turbocharged engines are not. So now we need less horsepower from each engine, in this case 150 hp each. Looking at the data for these engines we see that they will now have to run at 2,350 RPM to achieve 150 hp: 15 knots requires 300 hp (or 150 hp per engine) 150 hp requires 2,350 RPM 2,350 RPM burns 8.8 GPH per engine 15 knots / 17.6 GPH = 0.85 MP Gas consumption per hour= horsepower/15, how much gasoline would an engine burn with the following horse-power and given time of operation? a 40 ph for 4 hours? A 25 hp for 3 hours? A 90 hp for 6 hours? A 6 hp for 9 hours? Write the formula for your family's outboard motor gas consumption The Tesla Model 3 is an electric four-door fastback mid-size sedan developed by Tesla. The Model 3 Standard Range Plus version delivers an EPA-rated all-electric range of 263 miles (423 km) and the Long Range versions deliver 353 miles (568 km). According to Tesla, the Model 3 carries full self-driving hardware, with periodic software updates adding functionality The more you use the treadmill, the more energy it consumes. If an hour is 1.5 KWh, two hours are 3 KWh, and so on. However, depending on how much and how the treadmill is used, it also determines the amount of energy consumption. The treadmill engine (main power source) does not always use the maximum power

warranty. HP shall not be liable for technical or editorial errors or omissions contained herein. 4AA2-XXXXENUC, December 2008 Calculating Your Energy Consumption How to calculate HP Workstation energy consumption: With the correct tools, it is easy to calculate your energy consumption. First, it is important to know the daily power usage So the power conversion of horsepower to kilowatts is given by: P (kW) = 0.745699872 ⋅ P (hp) Example. Convert 10 hp to kW: P (kW) = 0.745699872 ⋅ 10hp = 7.45699872 kW . Electrical horsepower to kilowatts. One electrical horsepower is equal to 0.746 kilowatts: 1 hp(E) = 746 W = 0.746 kW. So the power conversion of horsepower to kilowatts is. Even some of the last 1/3 is lost in the actual running of the engine, friction, alternator drag etc. So we can calculate the thermal efficiency of an engine with this. TE = thermal efficiency . PPH = pound per hour fuel consumption . HP = TE x Fuel flow (PPH) x 19,000 (BTU per #) / 2545 (BTU per HP per hour) HP = TE x Fuel flow (PPH) x 7.46

1 unit induction motor power rated 25 hp,200 VAC,3 phase,90 % power factor,calculated the full load ampere. Calculation :-kW = 25 hp x 0.746 60 multiply by 0.746 as converting ratio you will get watts per hour and multiple for 12 hour is 44.760 kilowatts per hour multiple for 12 hour is 537.12 for 12 hour, calculate this kw multiple ain. Hours Used Per Day: Enter how many hours the device is being used on average per day, if the power consumption is lower than 1 hour per day enter as a decimal. (For example: 30 minutes per day is 0.5) Power Use (Watts): Enter the average power consumption of the device in watts. Price (kWh): Enter the cost you are paying on average per kilowatt hour, our caculators use the default value of 0. The motor is using a ton of power every second it is running on the order of 100 kwatts. Turning it off even for a second is going to save a dramatic difference in overall power consumption. If you ran the engine for just 1 second you're talking about 2.3 Amp-Hrs (assuming all that power is compared to a 12V battery producing 100 kwatts) Brake horse power is the power that a brake would have to absorb to stop a motor output and is how most motors (power output) and also pumps (required power in) are specified. Where: = Brake Horse Power (hp) = Flow rate (gpm) = Pressure (psi) = Water Pump Efficiency (decimal) And: Where: = Drive Motor Efficiency (decimal

A kilowatt-hour is 1,000 watts used for one hour. As an example, a 100-watt light bulb operating for ten hours would use one kilowatt-hour. How to calculate electric usage cost: 1. Volts x Amps = Watts 3. Kilowatts (kW) x Hours of Use = Kilowatt Hours (kWh) 4. Kilowatt Hours (kWh) x kWh rate = Cost of Usage 5. Add TVA Power Cost Adjustment. If you assume the efficiency is about 80% (pretty safe), then the Input power would be 1 / 0.8 or 1.25x the output horsepower, in order to deliver that much power. Also if the motor is three phase you can reduce the amps by 1.73 when converting from watts to FLA. There is more but this is the basics 1,5 hp=746*1.5 = 1119 watts .for 1 hour energy consumed is 1.119Kwh at 100% efficiency, You can take it as 1.12 units but it may be 1.5 units per hour at 75% efficienc 50 HP x 746 Watts/ HP = 37,300 Watts or converting to kiloWatts (kW) = 37.3 kW A motor of this size probably typically has an efficiency of 90% to 93% (0.90 to 0.93). For our purposes, assume the. ### How to Calculate 3 Phase Motor Power Consumption It

The power consumption for each light we worked out earlier to be 1.67 amps. So for three lights we calculate a current draw of 5 amps. So to calculate the power consumption we multiply 5 amps by 4 hours to get the result of 20 amp-hours per day This chart approximates the fuel consumption of a diesel generator based on the size of the generator and the load at which the generator is operating at. Please note that this table is intended to be used as an estimate of how much fuel a generator uses during operation and is not an exact representation due to various factors that can. There are many variations of Horse Power (HP) calculations found in historical and individual manufacturer's literature. The formulas below are used to determine the power requirements of a Bucket Elevator throughout the industry. Equation 1 - Power Formula. A basic power calculation is the measure of force over a distance per time period One horsepower is equal to 746 watts. Example: A 3/4-hp motor operates 8 hours a day. How much power is converted by the motor per month? How many kWh does this represent? Given: t = 8 hrs x 30 days P = 3/4 hp Solution: Convert horsepower to watts P = hp x 746 watts P = 3/4 x 746 watts P = 559 watts. Convert watts to watt-hours P = work x tim If the kilowatt-hour is then multiplied by the local rate of electricity, such as 8.5 cents per kilowatt-hour, then the dollar amount per year can be calculated. Keep in mind that higher horsepower values, from 0.5 hp to 5 hp, consume more power with their varying wattages .20KV√3 Example: Motor 10 HP, 460V, 3 phase, find I NEC 430-150, 10 HP @ 460V, 3 phase I = 14 Amp 3. KW, KVA KW is real consumed power turned into heat, and is the product of volts x current x power factor. KVA is apparent power, is always greater than or equal to KW and is the product of volts x amps 1 phase, volts x amps x , √3, 3 phase Consumption (CFM) Consumption (CFM) Consumption (CFM) Miscellaneous 15% Use FACTOR 25% Use FACTOR 35% Use FACTOR Rammers, Small 4 3 9 Rammer, Medium 5 9 12 Rammers, Large 6 10 14 Backfill Tamper 4 6 9 Compression Riveter 0.2 cu. ft. per cycle Air Motor, 1 HP 5 9 12 Air Motor, 2 HP 11 18 25 Air Motor, 3 HP 14 24 33 Air Motor Hoist, 1000# 1 cul. * Assuming \$0.10 per KWH. As expected it took more electricity to run faster. In fact, there doesn't appear to be much of a power savings by running faster. Plus it gets a bit dicey once you get past 7 miles/hour on a treadmill. Treadmill Power Consumption: Incline. In this test I ran 6.0 miles per hour at different inclines ### Energy Calculators Prism Engineerin

1 HP =0.745699872 kilowatts. So 5 HP =0.745699872 kilowatts X 5 =3.72849936 kilowatts . That means in One Hour 5 hp motor will consume 3.72849936 Units of electricity. So in one day=24 hrs the motor will consume 24 X 3.72849936=89.49 Units Per day (in 24 Hours) Consumers are only billed for active power, watts. Unslee you know the power angle you can't calculate the amount of active power from the information given. However, if you know the hp rating of the motor you can simply multiply that by 746, which will convert hp to watts. Then dived by 1000 to get kW and then figure out cost as per the.

Efficiency is assumed in this example to be 100% (hence 1.0 in the formula, but in reality is lower). If the pump runs 30 minutes it has used 1 KWh, 1 hour = 2 KWh, if for 2 hours = 4 KWh, and so on. Multiply KWh rate (\$) x KHw used to find total cost of operation. You will need your cost per kilowatt hour and gallon per minute of your pump Brake-specific fuel consumption (BSFC) is a measure of the fuel efficiency of any prime mover that burns fuel and produces rotational, or shaft power. It is typically used for comparing the efficiency of internal combustion engines with a shaft output.. It is the rate of fuel consumption divided by the power produced. It may also be thought of as power-specific fuel consumption, for this reason 3/4 HP Pro Snap Action Sump Pump The Everbilt 3/4 HP submersible sump pump The Everbilt 3/4 HP submersible sump pump is constructed of heavy-duty cast iron and features a PSC motor for energy efficiency and savings. The fasteners for the HDS75 are corrosion resistant stainless steel and the pump is protected by a powder coated epoxy finish HP is a unit of power, and as power is energy per time, power per hour is a meaningless concept. 1 HP is 746 watts, so 50 HP = 37300 watts or 37.3 kW. If you want the energy used per hour, that is 37.3 kW-hour.

### How much power consumes a 5hp 3 phase motor in 1 hour

Brand: Shreedhar. Operation Mode: Manual. Power Rating: 1-5 HP. Warranty: 7-12 months. Certification: CE, ISO, ISI. Voltage: 160-240 A 20 HP motor, at 746 watts per 1 HP, uses about 14920 watts. Call that 15KW. Putting aside questions of efficiency and duty cycle (and the irrelevant issue of voltage) the 15000 watts is a close approximation of what it will use per hour 1/2 HP Garage Door Opener Hair Dryer - 1250 Watts Curling Iron WORK DIY / Jobsite Quartz Halogen Work Light Airless Sprayer - 1/3 HP Reciprocating Saw Electric Drill - 3/8 in., 4 Amps Electric Drill - 1/2 in., 5.4 Amps Circular Saw - 7 1/4 in. Belt Sander Air Compressor - 1/4 HP Air Compressor - 1 HP Computer w/17 in. Monitor Fax. Electric Motor Calculator - Calculate amps, hp and kVA Electric Motor Efficiency - Calculate electric motor efficiency Electrical Induction Motors - Synchronous Speed - The speed at which an induction motor operates depends on the input power frequency and the number of electrical magnetic poles in the motor How to use the motor FLC calculator: The above tool requires following data for calculation: Motor Type - Single-phase or three-phase. (Mandatory) Motor rated power in HP or kW. (Mandatory) Input supply voltage. (Mandatory) Motor Efficiency as per nameplate - (if known). Rated power factor (if known)  ### How many kWh does a 2 hp motor use

The next item to look at for generator sizing is the volt-amperes (wattage) requirement of electric motor to be operated (e.g., furnace blower motor 1/3 HP), remembering that the starting requires 2 to 3* times the nameplate or running (rated) watts. Thus, if running watts of the motor is 600, multiply the number by 3 to determine approximate max *L = Liter per Hour / RPM Select Volvo Penta Diesel Test Model HP Fuel consumption WOT Boat owner? Volvo Penta Diesel D1 13. 13 hp: 3.10 LPH: Volvo Penta Diesel D1 20. 20 hp: 4.45 LPH: Volvo Penta Diesel D1 30: 30 hp: 6.60 LPH: Volvo Penta Diesel D2 75: 75 hp: 18.0 LPH: Volvo Penta Diesel D3 110: 110 hp 1 kW = 1.34 hp; 1 hp = 0.746 k W; Example - Heat Loss from an Electric Motor. The heat loss from an electric motor supplied with 10 kW can with the heat loss 150 watts/kW from the table above be calculated as (10 kW) (150 watts/kW) = 1500 watts = 1.5 kW. The rest of the energy (10 kW) - (1.5kW) = 8.5 kW. is output mechanical energy Search with Google catalogs of engine manufacturer. They indicate consumption, generally, in grams / hp-hour. (about 200 gr/hp-h) They do not say that consumption occurs under ideal navigation conditions, with the engine at 80%, but is data that can be used with caution. See attached example

### How many units of electricity will be consumed if we run a

The point is it is futile to try to estimate the power drawn by a lightly loaded motor without knowing the power factor. Rememember, the reactive current does not change with the load and as a result the power factor of a lightly loaded motor is very low. 250 HP x 746 = 186500, or 186.5 KW 2300V x 59.5A x 3^.5 = 237031 or 237 KV At 1800 rpm, a motor develops a 3 lb.ft. per hp At 1200 rpm, a motor develops a 4.5 lb.ft. per hp At 575 volts, a 3-phase motor draws 1 amp per hp At 460 volts, a 3-phase motor draws 1.25 amp per hp At 230 volts a 3-phase motor draws 2.5 amp per hp At 230 volts, a single-phase motor draws 5 amp per hp Motor Data Plate HP (EX: 25HP) X 110% = 27.5 HP Most Air Compressors @ Max PSI Use 110% of the rated Horsepower . KILOWATTS per HP =.746 watts 746 watts per hour of electrical energy is required to convert to 1 Horsepower of mechanical energy. KWH= your cost per 1000 watts of electrical energy per hour Mercury 4-stroke Outboard Motor Fuel Consumption Chart | Mercury 25 efi : 2.40 GPH | Mercury 50 efi : 4.65 GPH | Mercury 75 efi : 7.60 GPH | Mercury 90 efi : 10.0 GPH | Mercury 115 efi : 10.6 GPH | Mercury 150 efi : 14.2 GPH | Mercury Verado 200 efi : 19.9 GPH | Mercury Verado 225 efi : 23.1 GPH | Mercury Verado 250 efi : 27.9 GPH | Mercury Verado 350 SCi : 33.0 GPH | Mercury 400R Racing : 33.   Electric power consumption is rated power divided by motor efficiency. Rated power depends on class of motor (which corresponds to a \$200,000 per year power bill). Consequently, most customers to whom PF PF = 0.82 and motor with nameplate info of 100 hp and 94% efficiency The power consumption rating is represented by 5 stars. Out of that, the number of colored stars indicates the efficiency of the refrigerator. However, there is one major drawback in this standard for measuring power consumption. If the refrigerator becomes old, it becomes less efficient. Energy Saving Tips to Reduce Power Consumption Evinrude Etec 2-stroke Outboard Fuel Consumption Evinrude Etec 25 hp 2.55 GPH | Evinrude Etec 50 hp 4.55 GPH | Evinrude Etec 75 hp 6.80 GPH | Evinrude Etec 90 hp 7.70 GPH | Evinrude Etec 115 hp 10.7 GPH | Evinrude Etec 150 hp 15.1 GPH | Evinrude Etec 225 hp 21.5 GPH | Evinrude Etec 250 hp 23.4 GPH | Portable 4-stroke 3.5 - 4 - 6 - 9.8 - 15 hp | US Gallons per hour | Also Fuel usage Liters and. Annual energy consumed by a light bulb is calculated by multiplying the power (43 watts) by the average daily use (3 hours/day) by the number of days per year (365). Assuming an average daily use of 3 hours per day, an incandescent bulb consumes 47.1 kWh per year, and an LED bulb consumes 9.9 kWh per year (EPA 2019) I have a leisure spa with a 3 hp pump at 115/230 volt. Amperage at 115 volts says 16.6. amps At 230 volts 8.8 amps. What happens is it is drawing 24 to 28 amps at 115 volts with a load. Installed new wet end and seals per XPS motor and pump. It blew the circuit relay way before I put new wet end on. Soldered new relay and works again

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